4^x=(1/128)

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Solution for 4^x=(1/128) equation: 



4^x=(1/128)

We move all terms to the left:

4^x-((1/128))=0

We add all the numbers together, and all the variables

4^x-((+1/128))=0

We multiply all the terms by the denominator


4^x*128))-((+1=0

Wy multiply elements

512x^2+1=0

a = 512; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·512·1
Δ = -2048
Delta is less than zero, so there is no solution for the equation

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